reduce or not possible

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ok my uncle got the pump for the waterfalls its a little giant f series I think like 7600 gph problem is the outlet on the pump is 2'' and the hose we already have is 1 1/4 inside diameter. now can I just put a reducer on this and use the hose we have or should we get a 2'' hose for it they are pretty expensive for a hose that high


do you think it will harm the pump to use the smaller hose
 
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davepratt said:
ok my uncle got the pump for the waterfalls its a little giant f series I think like 7600 gph problem is the outlet on the pump is 2'' and the hose we already have is 1 1/4 inside diameter. now can I just put a reducer on this and use the hose we have or should we get a 2'' hose for it they are pretty expensive for a hose that high


do you think it will harm the pump to use the smaller hose
If I was you (or your Uncle) I'd contact the guys at Little Giant directly and ask them that question. I suspect you could get away with it without harming the pump, but for sure you'll get reduced performance.
They have a toll free support #
http://little-giantpump.com/
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800-701-7894

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sissy

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I used just a plain T fitting and used hose clamps to hold it on .I glued in extended pieces to the T and hose clamps to hold the hose on and it works great .
 
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Does the pump come with a reducer ?
If so I would say that you can but if you found no reducer then it would be a no , however as has been suggested you can always contact the company or perhaps down load the plans to have a look .

rgrds

Dave
 
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Pipe size only effects how much water is moved, doesn't hurt the pump to have a smaller pipe.

Pipe size also effects how much electric the pump uses.

Those things can all be calculated but here are some ballpark numbers assuming a length of 10' and PVC pipe.

Pipe size Head Loss PSI
1.25".........-22ft.............9.6
1.5"...........-4.3..............1.9
2"..............-1.3..............0.6
3".............-0.2...............0.1
4".............-0.1...............0.0

As you can see the PSI (pounds per square inch) of water inside the pipe drops as the pipe size gets bigger. For a pond we don't need water pressure, we only care about the amount of water moved. Just like your garden water hose, when you reduce the volume of water at the nozzle the water squirts out further.

What this means is, again ballpark, is your 7600 GPH pump would only move about one half to one third as much water with a 1.25" pipe as 2" or 3" pipe. Or you can look at it as having to pay twice as much for the cost of the pump and electric to move the same amount of water compared to buying a smaller pump and using the same size pipe.

In general, the fitting on a pump's discharge should be stepped up. There are complex technical reasons why the discharge on a pump is smaller than the pipe should be (pump needs higher pressure to prevent back flow), but the faster you scale up the pipe size the faster you reduce pressure in the pipe and the more water can move.

So a pump with a 2" discharge should have a 2" x 3" Reducing Male Adapter, MPT x Slip screwed into the pump discharge. Then you can glue 3" PVC pipe to the added fitting.

However, like I said at the beginning, you can use any size pipe and adapter you like, the pump will move some water.
 
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dieselplower said:
Waterbug does a pump use more electricity when it has to push water out at a higher pressure? Does it increase the "load" on the pump? I have wondered this for a while.
Same thing here .

rgrds

Dave
 
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dieselplower said:
Waterbug does a pump use more electricity when it has to push water out at a higher pressure? Does it increase the "load" on the pump? I have wondered this for a while.
Simple answer is yes.

The complex answer is it depends on the pump and which heads are actually being used. You might be familiar with the basic formula for computing watts?

amps x volts = watts

For lots of things (toaster, UV filter, etc) that formula works. But for inductive devices (for example motors with magnets like most water pumps) another variable has to be added to the formula called "power factor".

amps x volts x power factor = watts

"Power factor" is complex but basically electric is used to push a motor's magnet. That we understand. The thing most people will be surprised by is that as the magnet comes around it pushes some electric back to the power company. So if the motor consumes 50 watts and returns 10 watts, you will only be billed for 40 watts. For a water pump it would be labeled as a 50 watt pump, meaning that's the max power it will draw. But in this specific case it actually is only using 40 watts. Now if that same pond is changed to say add a higher waterfall, or the pipe size is reduced, there would be more pressure the pump would have to push against, so maybe now it could only return 2 watts to the power company and now that same pump is costing you 50 - 2 = 48 watts to operate.

Higher end pump manufacturers using electric motors will publish their test data showing the flow at different heads and also the watts used at different heads/flow. So if a person wanted to pick the lowest cost pump to run they'd need to know the actual head because different pumps perform differently at different heads. If that sounds complex...it is.
 
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Wow lot of great info there thanks everyone i ended up getting a wye with two 1.5 inch outlets giving me 3 inch total it working great definitely moves so water
 

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